Definition of what an energy band is?

lotrsimp12345
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is this correct?
An energy band is a continuous distribution of similar energy levels?

What is the reason for energy bands in solids?
The reason is there is a close proximity of many atoms which is because the energy difference becomes very small. So the energy is bundled together rather than representing indivual energy levels.
 
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The last answer sounds odd. Let's say you have a lot of spaced out atoms with discrete energy levels. As they get closer to each other, the wavefunctions will overlap and those discrete energy levels will lose their degeneracy and begin to spread out. As they spread out, you get a range in energy that the electrons can live in, basically a band. So it is due to this periodicity with overlapping wavefunctions that you get bands.
 
Hmm... Just realized you double posted this. Please don't post the same question in multiple threads.
 
now my question is how would you know what states the s-band can have?
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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