- #1
AntiStrange
- 20
- 1
I'm reading through the Introduction to Quantum Mechanics book by Griffiths (2nd edition)
and it is describing delta-function potential wells.
When it describes how to find bound states the energy is E < 0 (negative) in the region x < 0 (negative).
It says the general solution is:
[tex]\psi (x) = Ae^{-\kappa x} + Be^{\kappa x}[/tex]
It explains that as x goes to -∞ the first term blows up. Which makes sense because it will go to infinity, while the second term only goes to zero.
However, they then look at the situation when E > 0, x < 0
again the general solution is:
[tex]\psi (x) = Ae^{-\kappa x} + Be^{\kappa x}[/tex]
but this time they say that neither term blows up. I don't understand why that is. Shouldn't the first term still go to infinity as x goes to -∞ ?
and it is describing delta-function potential wells.
When it describes how to find bound states the energy is E < 0 (negative) in the region x < 0 (negative).
It says the general solution is:
[tex]\psi (x) = Ae^{-\kappa x} + Be^{\kappa x}[/tex]
It explains that as x goes to -∞ the first term blows up. Which makes sense because it will go to infinity, while the second term only goes to zero.
However, they then look at the situation when E > 0, x < 0
again the general solution is:
[tex]\psi (x) = Ae^{-\kappa x} + Be^{\kappa x}[/tex]
but this time they say that neither term blows up. I don't understand why that is. Shouldn't the first term still go to infinity as x goes to -∞ ?