Density and circumference relationship? From Example in book

AI Thread Summary
The discussion focuses on understanding the linear mass density of a circular ring, specifically why it is defined as mass over circumference rather than mass over volume. The relationship is clarified as the ring is a two-dimensional object, where density is expressed in terms of its geometry. Additionally, the notation for the infinitesimal mass element, dM, relates to the angle phi, indicating how mass is distributed along the arc length of the ring. The participants seek clarity on these concepts to solve the equilibrium problem presented in the textbook example. Understanding these foundational principles is essential for progressing in the dynamics problem.
unicornflyers
Messages
8
Reaction score
0

Homework Statement


Example 5.3 from The Marion Thornton book (fifth edition) of Classical Dynamics states the following problem:

Consider a thin uniform circular ring of radius a and mass M. A mass m is placed in the plane of the ring. Find a position of equilibrium and determine whether it is stable. I'm following the example in the book, and there's two things I don't understand. First is why /rho = \frac{M}{2*/pi * a}. I always thought that the density was the mass over the volume, so I don't see why this is mass over circumference.

Second, in the next piece, it says that d\Phi = -G \frac{dM}{b} = \frac{-Ga\rho}{b}d\phi

I'm failing to see two things. 1) why the dM element ends up with a small phi, and 2) why rho is as it is. From here, I believe I can find the rest of the example, but why are these two things true?
 
Physics news on Phys.org
The textbook is apparently using the symbol ##\rho ## to denote the linear mass density.

An infinitesimal arc length can be written in terms of ##d \phi##.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top