(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Density/Sea Water Problem

Assume the density of sea water is 1024 kg/m^3 and take the atmospheric pressure equal to 101000Pa. The acceration due to gravity is 9.8m/s^2. Calculate the pressure at an ocean depth of 1260m. Answer in Pa.

Calculate the total force exerted on the outside of a circular submarine window of a diameter of 27.2cm at this depth. Answer in units of N.

p=m/v | P=F/A | P=pgh

p=density, P= pressure, F=force, A=area, g=gravity, h=height

For this problem, I used P=pgh without regard to the pascals. Then for part II, I used my pressure from the first part and plugged it into P=F/A... I used the area of the submarine window with a diameter of 27.2. Neither got me the right answer.... and I'm not sure what equations to use now.

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# Homework Help: Density/Sea Water Problem

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