Engineering Dependent source problem using KVL

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The discussion addresses a problem with applying Kirchhoff's Voltage Law (KVL) in circuits involving dependent sources. The original poster is confused about their simulation results, specifically the current values and the negative power of the dependent current source. A suggestion is made to consider the voltage across the current source, as it may have been incorrectly assumed to be zero. Additionally, the importance of using the super mesh technique when dealing with shared current sources in mesh analysis is emphasized. Proper application of these techniques is crucial for accurate circuit analysis.
Michael_0039
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Homework Statement
Using KVL find the current through the resistors and Power of the dependent current source.
Relevant Equations
nil
Hi all,

I was trying to solve this but I'm stuck as you can see in my notes below:

New Doc 2019-10-13 16.55.53_1.jpg

New Doc 2019-10-13 16.55.53_2.jpg


Using simulator the I1=3.125 A | I2=-1,857 A | I3=4,375 A and Power of the dependent current source = -46.875 W

1570976039548.png


Any idea, what could be wrong ?Thanks.
 
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In your loop 2 equation you're ignoring the voltage across the current source? So are you pretending it's zero volts?
 
Michael_0039 said:
Using simulator the I1=3.125 A | I2=-1,857 A | I3=4,375 A and Power of the dependent current source = -46.875 W

View attachment 251072


Any idea, what could be wrong ?Thanks.

Since mesh1 and mesh2 share a current source, you must use the super mesh technique, combining mesh1 and mesh2 for your second equation. Have you learned the super mesh technique?
 
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