Derivation of Acceleration from Velocity with Partial derivatives

Click For Summary
SUMMARY

The discussion centers on deriving acceleration from velocity using partial derivatives in fluid mechanics. The key equation presented is the relationship between acceleration and velocity, expressed as vec{a} = frac{dvec{V}}{dt} = frac{partial vec{V}}{partial t} + frac{partial vec{V}}{partial x}frac{dx}{dt} + frac{partial vec{V}}{partial y}frac{dy}{dt} + frac{partial vec{V}}{partial z}frac{dz}{dt}. Participants emphasized understanding the chain rule for partial derivatives as essential for grasping this concept. A helpful resource was provided, linking to a detailed explanation of the chain rule.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with vector calculus
  • Knowledge of partial derivatives
  • Basic proficiency in mathematical notation and equations
NEXT STEPS
  • Study the chain rule for partial derivatives in depth
  • Explore vector calculus applications in fluid dynamics
  • Practice deriving acceleration from velocity using various examples
  • Review resources on the mathematical foundations of fluid mechanics
USEFUL FOR

Students in fluid mechanics, mathematicians focusing on calculus, and anyone seeking to understand the relationship between velocity and acceleration through partial derivatives.

fluidmech
Messages
17
Reaction score
1

Homework Statement


I'm taking a fluid mechanics class and I'm having an issue with acceleration and background knowledge. I know this is ridiculous, but I was hoping someone might be able to explain it for me.

Homework Equations


I definitely understand:
##a=\frac{d\vec{V}}{dt}##

And I know that u, v, and w are components of the velocity, ##\vec{V}=<u,v,w>##

But how do I use the chain rule of differentiation to get to:

##\vec{a}=\frac{d\vec{V}}{dt}=\frac{\partial \vec{V}}{\partial t} +\frac{\partial \vec{V}}{\partial x}\frac{dx}{dt} +\frac{\partial \vec{V}}{\partial y}\frac{dy}{dt} +\frac{\partial \vec{V}}{\partial z}\frac{dz}{dt}##

Thanks in advance!

- Matt
 
Physics news on Phys.org
fluidmech said:

Homework Statement


I'm taking a fluid mechanics class and I'm having an issue with acceleration and background knowledge. I know this is ridiculous, but I was hoping someone might be able to explain it for me.

Homework Equations


I definitely understand:
##a=\frac{d\vec{V}}{dt}##

And I know that u, v, and w are components of the velocity, ##\vec{V}=<u,v,w>##

But how do I use the chain rule of differentiation to get to:

##\vec{a}=\frac{d\vec{V}}{dt}=\frac{\partial \vec{V}}{\partial t} +\frac{\partial \vec{V}}{\partial x}\frac{dx}{dt} +\frac{\partial \vec{V}}{\partial y}\frac{dy}{dt} +\frac{\partial \vec{V}}{\partial z}\frac{dz}{dt}##

Thanks in advance!

- Matt

You want to think of V as a function of four variables V(t,x,y,z).
 
I see, I'm still a bit hazy on the mathematics of the partials, would you mind elaborating on that?
 
Last edited:
fluidmech said:
I see, I'm still a bit hazy on the mathematics of the partials, would you mind elaborating on that?

Look up the chain rule for partial derivatives. E.g. http://mathworld.wolfram.com/ChainRule.html
 
That helped me tremendously. Now I understand it, thank you!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
1K
Replies
8
Views
2K
Replies
12
Views
2K
Replies
15
Views
1K
  • · Replies 29 ·
Replies
29
Views
2K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
2K
Replies
13
Views
2K