Derivation of Acceleration from Velocity with Partial derivatives

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Homework Help Overview

The discussion revolves around the derivation of acceleration from velocity in the context of fluid mechanics, specifically focusing on the application of the chain rule of differentiation. The original poster expresses confusion about how to relate acceleration to the components of velocity using partial derivatives.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between acceleration and velocity components, questioning how to apply the chain rule in this context. Some participants suggest looking into the chain rule for partial derivatives to clarify the mathematical approach.

Discussion Status

The discussion is progressing with some participants providing guidance on the mathematical concepts involved. The original poster indicates that they found the information helpful, suggesting a positive direction in understanding the topic.

Contextual Notes

The original poster mentions a background knowledge issue, implying that there may be gaps in their understanding of the underlying mathematics necessary for fluid mechanics.

fluidmech
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Homework Statement


I'm taking a fluid mechanics class and I'm having an issue with acceleration and background knowledge. I know this is ridiculous, but I was hoping someone might be able to explain it for me.

Homework Equations


I definitely understand:
##a=\frac{d\vec{V}}{dt}##

And I know that u, v, and w are components of the velocity, ##\vec{V}=<u,v,w>##

But how do I use the chain rule of differentiation to get to:

##\vec{a}=\frac{d\vec{V}}{dt}=\frac{\partial \vec{V}}{\partial t} +\frac{\partial \vec{V}}{\partial x}\frac{dx}{dt} +\frac{\partial \vec{V}}{\partial y}\frac{dy}{dt} +\frac{\partial \vec{V}}{\partial z}\frac{dz}{dt}##

Thanks in advance!

- Matt
 
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fluidmech said:

Homework Statement


I'm taking a fluid mechanics class and I'm having an issue with acceleration and background knowledge. I know this is ridiculous, but I was hoping someone might be able to explain it for me.

Homework Equations


I definitely understand:
##a=\frac{d\vec{V}}{dt}##

And I know that u, v, and w are components of the velocity, ##\vec{V}=<u,v,w>##

But how do I use the chain rule of differentiation to get to:

##\vec{a}=\frac{d\vec{V}}{dt}=\frac{\partial \vec{V}}{\partial t} +\frac{\partial \vec{V}}{\partial x}\frac{dx}{dt} +\frac{\partial \vec{V}}{\partial y}\frac{dy}{dt} +\frac{\partial \vec{V}}{\partial z}\frac{dz}{dt}##

Thanks in advance!

- Matt

You want to think of V as a function of four variables V(t,x,y,z).
 
I see, I'm still a bit hazy on the mathematics of the partials, would you mind elaborating on that?
 
Last edited:
fluidmech said:
I see, I'm still a bit hazy on the mathematics of the partials, would you mind elaborating on that?

Look up the chain rule for partial derivatives. E.g. http://mathworld.wolfram.com/ChainRule.html
 
That helped me tremendously. Now I understand it, thank you!
 

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