Derivation of angular frequency equation

AI Thread Summary
To derive the angular frequency equation ω=√(g/L), start with the second-order differential equation ((d^2)θ)/(dt^2) = (-g/L)θ. Use the equation θ=θmaxcos(ωt+δ) to find the second derivative of θ with respect to time. The constant θmax can be treated as a constant during differentiation. Setting the second derivative equal to the original equation will lead to the desired expression for angular frequency. This process clarifies the relationship between angular frequency and the parameters g and L.
AToMic93
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Homework Statement


Derive the angular frequency equation (ω=√(g/L) from following equations:


Homework Equations


1) ((d^2)*θ)/(d*t^2)= (-g/L)*θ
2) θ=θmaxcos(ωt+δ)

The Attempt at a Solution


I don't even know where to start
 
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AToMic93 said:

Homework Statement


Derive the angular frequency equation (ω=√(g/L) from following equations:


Homework Equations


1) ((d^2)*θ)/(d*t^2)= (-g/L)*θ
2) θ=θmaxcos(ωt+δ)

The Attempt at a Solution


I don't even know where to start

(1) tells you that ##\frac{d^2\theta}{dt^2}## is (-g/L)θ. (2) gives you a formula for θ. If you were only given (2), how would you find an expression for ##\frac{d^2\theta}{dt^2}## from it?
 
Would you take the second derivative with respect to time? (giving d2/dt2) then set this equal to the other equation?
 
AToMic93 said:
Would you take the second derivative with respect to time? (giving d2/dt2) then set this equal to the other equation?

I suggest you give it a try :wink:
 
So the main question I have then is for when I'm deriving how do I deal with the θmax? Do I treat it just like θ or do I treat it like a constant?
 
AToMic93 said:
So the main question I have then is for when I'm deriving how do I deal with the θmax? Do I treat it just like θ or do I treat it like a constant?
It is, of course, a constant. But do keep in mind that θ = θmaxcos(ωt + δ) :wink:
 
Alright I got it. Thanks
 
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