Derivation of lattice parameter of zinc blende crystal structure

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The discussion focuses on deriving the lattice parameter of the zinc blende crystal structure in relation to the Zn-S separation distance, denoted as l. The derived formula presented is a = 4/√3 * l, based on geometric relationships within the crystal structure. An isosceles triangle is formed with the sulfide ion at the center and two adjacent zinc atoms, leading to the calculation of side x using the law of cosines. The confusion arises in relating x to the lattice parameter a, with initial assumptions leading to incorrect conclusions about the bond angle. The correct bond angle is identified as arccos(-⅓), resolving the derivation issue.
emmanuelpn
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I need to derive the lattice parameter in terms of the Zn-S separation distance, l.

I looked up the value and I've found it to be
a = \frac{4}{\sqrt{3}}l

The way that I started my derivation was saying that each tetrahedron has a sulfide ion in the center, so then we can make a triangle from the center point, and two zinc adjacent atoms. This isosceles triangle will have an angle
θ = cos-1\frac{1}{3}
with two equal sides of the separation distance l, and an opposite side of the angle θ, let's call it x. Finding x is then easy using the law of cosines.
x2 = 2l2 – 2l2cosθ
then
x = \frac{2}{\sqrt{3}}l

Now, I'm having a hard time relating x to a. And the only way it seems to work out to get the answer I looked up is by saying a = 2x. But from the crystal structure, my mind tells me \sqrt{2}a = 2x.

Does anyone know what's going on?

 
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Found my mistake! the bond angle is arcos(-⅓)!
 
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