Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1

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In summary, the conversation is about finding the derivative of a function P(x) = 0.2 -0.125e^(0.005x) for x=1, where P(x) represents the population in millions and x represents the year. The conversation includes a discussion on the correct method for calculating the derivative and the conclusion is that since the derivative is negative, the population is decreasing over time.
  • #1
masterchiefo
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Homework Statement


Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1
P(x) is the population in Millions and X is the year where 0 = 2000
I have to explain the answer I am getting at the end.

Homework Equations

The Attempt at a Solution


d/dx (0.2 -0.125e^(0.005x))
I find -0.000625*(1,00501)^x // did this with my calculator
-0.000625*(1,00501)^1 = -0.000628

does that simply mean that the population is going down over time?
 
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  • #2
Welcome to PF,
Great work, just want to point at something, P(x) = 0.2 -0.125*e^(0.005)
It has a something constant - some exponontial, so it will be decreasing so fast over the years,
Hope I've helped,
[Edit: To answer, you have to write down the derevative of P in terms of x, and what should it's sign be to be decreasing ?]
 
  • #3
masterchiefo said:

Homework Statement


Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1
P(x) is the population in Millions and X is the year where 0 = 2000
I have to explain the answer I am getting at the end.

Homework Equations

The Attempt at a Solution


d/dx (0.2 -0.125e^(0.005x))
I find -0.000625*(1,00501)^x // did this with my calculator
-0.000625*(1,00501)^1 = -0.000628
No.
I don't know what you entered into your calculator, but it came out wrong. The derivative should involve e raised to the power kx.

I would advise putting your calculator away and doing this by hand. You're more likely to get the right answer.
masterchiefo said:
does that simply mean that the population is going down over time?
 
  • #4
Mark44 said:
No.
I don't know what you entered into your calculator, but it came out wrong. The derivative should involve e raised to the power kx.

I would advise putting your calculator away and doing this by hand. You're more likely to get the right answer.
Thats because my calculator calculated e^0.005*x = 1.00501^x
 
  • #5
Noctisdark said:
Welcome to PF,
Great work, just want to point at something, P(x) = 0.2 -0.125*e^(0.005)
It has a something constant - some exponontial, so it will be decreasing so fast over the years,
Hope I've helped,
[Edit: To answer, you have to write down the derevative of P in terms of x, and what should it's sign be to be decreasing ?]
Yeah I wrote down the derevative of P in terms of x and I believe that since its negative the population is decreasing ?
 
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  • #6
Yepp, great work .
 
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  • #7
Noctisdark said:
Yepp, great work .
thanks awesome.

This forums makes me like University even more :) I love school & studying :)
 
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  • #8
masterchiefo said:
Thats because my calculator calculated e^0.005*x = 1.00501^x
Operator error

To make that calculation, you need parentheses, as in e^(.005*x).
 
  • #9
Noctisdark said:
Yepp, great work .
Please pay closer attention before making comments about the correctness of a poster's work. The OP made a gross error in his first post, which you apparently didn't notice.
 
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  • #10
Mark44 said:
Operator error

To make that calculation, you need parentheses, as in e^(.005*x).
oh ok thank you very much :)
 

What is the derivative of P(x) at x=1?

The derivative of P(x) at x=1 is 0.000625.

How do you calculate the derivative of P(x)?

The derivative of P(x) can be calculated using the power rule and the chain rule. In this case, the derivative is 0.005e^(0.005x).

What is the significance of the derivative in this equation?

The derivative represents the rate of change of P(x) at a specific point (x=1). It can also be interpreted as the slope of the tangent line to the curve at that point.

What is the overall trend of P(x) as x increases?

The overall trend of P(x) is a decreasing exponential function. As x increases, the value of P(x) decreases at a decreasing rate.

How can the derivative of P(x) be used in real-world applications?

The derivative of P(x) can be used in various fields such as physics, economics, and engineering to analyze rates of change and make predictions. For example, in economics, the derivative can be used to determine the marginal cost of production at a specific level of output.

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