Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1

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Homework Help Overview

The discussion revolves around finding the derivative of the function P(x) = 0.2 - 0.125e^(0.005x) at the point where X=1, with P(x) representing population in millions and X indicating years since 2000. Participants are exploring the implications of the derivative in terms of population trends over time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the derivative and its interpretation, with some questioning the accuracy of calculator results and suggesting manual calculations. There is also a focus on understanding the implications of a negative derivative in relation to population trends.

Discussion Status

The discussion is active, with participants providing feedback on each other's calculations and interpretations. Some guidance has been offered regarding the correct form of the derivative and the importance of notation in calculations. Multiple interpretations of the results are being explored, particularly concerning the implications of the derivative's sign.

Contextual Notes

There are indications of confusion regarding the use of calculators and the correct application of exponential functions, with participants noting the need for careful notation to avoid errors.

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Homework Statement


Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1
P(x) is the population in Millions and X is the year where 0 = 2000
I have to explain the answer I am getting at the end.

Homework Equations

The Attempt at a Solution


d/dx (0.2 -0.125e^(0.005x))
I find -0.000625*(1,00501)^x // did this with my calculator
-0.000625*(1,00501)^1 = -0.000628

does that simply mean that the population is going down over time?
 
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Welcome to PF,
Great work, just want to point at something, P(x) = 0.2 -0.125*e^(0.005)
It has a something constant - some exponontial, so it will be decreasing so fast over the years,
Hope I've helped,
[Edit: To answer, you have to write down the derevative of P in terms of x, and what should it's sign be to be decreasing ?]
 
masterchiefo said:

Homework Statement


Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1
P(x) is the population in Millions and X is the year where 0 = 2000
I have to explain the answer I am getting at the end.

Homework Equations

The Attempt at a Solution


d/dx (0.2 -0.125e^(0.005x))
I find -0.000625*(1,00501)^x // did this with my calculator
-0.000625*(1,00501)^1 = -0.000628
No.
I don't know what you entered into your calculator, but it came out wrong. The derivative should involve e raised to the power kx.

I would advise putting your calculator away and doing this by hand. You're more likely to get the right answer.
masterchiefo said:
does that simply mean that the population is going down over time?
 
Mark44 said:
No.
I don't know what you entered into your calculator, but it came out wrong. The derivative should involve e raised to the power kx.

I would advise putting your calculator away and doing this by hand. You're more likely to get the right answer.
Thats because my calculator calculated e^0.005*x = 1.00501^x
 
Noctisdark said:
Welcome to PF,
Great work, just want to point at something, P(x) = 0.2 -0.125*e^(0.005)
It has a something constant - some exponontial, so it will be decreasing so fast over the years,
Hope I've helped,
[Edit: To answer, you have to write down the derevative of P in terms of x, and what should it's sign be to be decreasing ?]
Yeah I wrote down the derevative of P in terms of x and I believe that since its negative the population is decreasing ?
 
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Yepp, great work .
 
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Noctisdark said:
Yepp, great work .
thanks awesome.

This forums makes me like University even more :) I love school & studying :)
 
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masterchiefo said:
Thats because my calculator calculated e^0.005*x = 1.00501^x
Operator error

To make that calculation, you need parentheses, as in e^(.005*x).
 
Noctisdark said:
Yepp, great work .
Please pay closer attention before making comments about the correctness of a poster's work. The OP made a gross error in his first post, which you apparently didn't notice.
 
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  • #10
Mark44 said:
Operator error

To make that calculation, you need parentheses, as in e^(.005*x).
oh ok thank you very much :)
 

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