Derivatives Adv Calc: Show f'(x) = f'(0)f(x)

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Homework Statement


function f is differentiable when x=0,

f'(0) is not equal to zero for all real Numbers

f(a+b) = f(a)f(b)

show f'(x) = f'(0)f(x)

Homework Equations


The Attempt at a Solution



f(x+0) = f(x) = f(x)f(0)
this shows f(0) = 1

then i get stuck..
 
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chief12 said:

Homework Statement


function f is differentiable when x=0,

f'(0) is not equal to zero for all real Numbers

What does "for all real numbers" have to do with f'(0)?

f(a+b) = f(a)f(b)

show f'(x) = f'(x)f(x)

You clearly haven't stated the problem correctly since f(x) = ex is a counterexample.
 
LCKurtz said:
What does "for all real numbers" have to do with f'(0)?



You clearly haven't stated the problem correctly since f(x) = ex is a counterexample.
\for some reason it quoted wrong i guess, it said f'(x) = f'(0)f(x)
 
Write f'(x) as a difference quotient.
 
What happens when you try to calculate f'(x) by taking the limit of the difference quotient?
 
LCKurtz said:
What happens when you try to calculate f'(x) by taking the limit of the difference quotient?

I don't know what that means, please explain... test tomorrow
 
LCKurtz said:
What happens when you try to calculate f'(x) by taking the limit of the difference quotient?

chief12 said:
I don't know what that means, please explain... test tomorrow

Surely the definition of a derivative is in your text:

f'(x) = \lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}
 
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