Derivatives of arctan((x+y)/(1-xy))

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Homework Statement



Find all second partial derivatives of
z=arctan((x+y)/(1-xy))

Homework Equations



d/dx of arctan(x) is 1/(1+x^2)

The Attempt at a Solution



Not sure how to proceed... I don't want the answer, just an idea as to how to move forward.

My attempt at finding the first derivative...

z'=(1/(1+(x+y/(1-xy)) * (x(1-xy) - (x+y(-y)) / (1-xy)^2

Is this correct? If it is, I honestly don't know how to find the second derivative...

On another note, can someone tell me how I can use math notation instead of plain text, to make the equations and such easier to read? Thanks guys.
 
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Take care of the parentheses. Check the derivative of the arctan function.

To make your task easier, remember the addition formula :
tan(\alpha+\beta)=\frac{tan(\alpha)+tan(\beta)}{1-tan(\alpha)tan(\beta)}
Can you write the function z(x,y) in a simpler form?
As for Math notations, go to "advanced" and click on the 'Σ'.
ehild
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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