DERIVE a 6x6 Hamiltonian for bulk semiconductors

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URGENT x 10 DERIVE a 6x6 Hamiltonian for bulk semiconductors

Okay here is a little challenge for you guys. Try and test your skill a little. First 10 people to properly derive a 6x6 Hamiltonian for bulk semiconductors will gain bragging rights in this forum.
 
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would a 6 x 6 be two 3x3s across the diagnol but symmetric?
h11 h12 h13 0 0 0
h21 h22 h23 0 0 0
h31 h32 h33 0 0 0
0 0 0 h11 h12 h13
0 0 0 h21 h22 h23
0 0 0 h31 h32 h33
 
Start with the 3 p-states, and use the \vec{k} \times \vec{p} Hamiltonian to work out the states...You have to include spin and utilize the spin-orbit corrections to get the correct form of the matrix. Worked the 8 \times 8 version for my dissertation years ago which involved the s-states.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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