Deriving a differential equation for a loan/interest problem

JNBirDy
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Homework Statement


You borrow money from a friend at a continuous interest rate of r% per month. You want to pay your friend back as quickly as you can at the beginning, but reduce your payment rate over time. You decide to pay off at a continuously decreasing rate given by K₀e^{-at}, in dollars per month.

Write a differential equation that describes how much you owe and solve it.


Homework Equations


None


The Attempt at a Solution


Let S be the amount borrowed -

dS/dt = rS - K₀e^{-at}

S' - rS = -K₀e^{-at}

S'(I(x)) - rS(I(x)) = -K₀e^{-at}(I(x))

Se^{-rt} = -K₀\inte^{-t(a+r)}

Se^{-rt} = ...

This is where I get stuck, I have don't understand how to integrate -K₀\inte^{-t(a+r)}, any hints?
 
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if 'a' and 'r' are constants then you can simply recall that ∫ ekt = (1/k)ekt+ constant.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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