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Deriving centroid of quarter circle.

  1. Apr 7, 2010 #1
    1. The problem statement, all variables and given/known data
    Find the centroid of the region cut from the first quadrant by the circle x^2+y^2=a^2


    2. Relevant equations
    I know that y' = (I y dA)/(I dA)


    3. The attempt at a solution
    Taking a strip dy with length x, I obtain dA = dy.x dy(a^2-y^2)^(1/2)

    So I y DA = I y*(a^2-y^2)^(1/2) dy from a->0

    This integral leads to a^(3/2)/3

    Now, I dA is simply 1/4 the area of a circle radius a = a^2.pi/4

    By dividing these 2 values, I obtain 4/3.pi.sqrt(a) instead of 4a/3pi which means I'm off by a sqrt a somewhere which I can't seem to figure out the error, I think the best bet would be the definite integral giving a^(3/2)/3 but even after plugging it in a few integrators, it comes out the same.

    Any help is greatly appreciated.

    EDIT :

    Oh dear me, I'm so silly. Forgot it was (a^2)^3/2 !
     
    Last edited: Apr 7, 2010
  2. jcsd
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