Deriving Formulas for Vmin & Vmax on Glare Ice w/ Zero Friction

  • Thread starter Thread starter fineztpaki
  • Start date Start date
  • Tags Tags
    deriving Formulas
fineztpaki
Messages
13
Reaction score
0

Homework Statement



A circular curve of radius R in a new highway is designed so that a car traveling at speed v can negotiate the turn safely on glare ice (zero friction). If a car travels too slowly, then it will slip toward the center of the circle. If it travels too fast, then it will slip away from the center of the circle. If the coefficient of static friction increases, a car can stay on the road while traveling at any speed within a range from vmin to vmax. Derive formulas for vmin and vmax using mu for µ, and v, R, and g as appropriate.

Vmin= ?
Vmax= ?

Homework Equations


How can i derive a formula for this?


The Attempt at a Solution


I've tried a couple but I don't know exactly how to do it. When i put my answer it comes out wrong. help?
 
Physics news on Phys.org
I got for vmin:
Vsqrt((1-mu(Rg)/(V^2))/(1+mu(V^2)/(Rg)))
but it keeps saying its wrong!??!?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top