Deriving the Coefficients of an Infinite Power Series

DanAbnormal
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Homework Statement



Show that if a function f(x) can be expressed as an infinite power series, then it has the form

f(x) = f(x0) + \sum^{\infty}_{n = 1}\frac{f^{n}(x0)}{n!}(x - x0)^{}

Homework Equations





The Attempt at a Solution



I know that for an infinite power series:

= f(a) + \frac{f'(a)}{1!}(x - a) + \frac{f''(a)}{2!}(x - a)^{2}...

which can be simplified into the above expression. But is there any groundwork that the question asks to get to this point here? I am thinking for 6 marsk i can't just right down the two lines...
 
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A power series has the form <br /> f(x)= \sum^{\infty}_{n = 0}<br /> a_n (x-a)^n. You want to show f_n(a)/n!=a_n. Differentiate the power series n times and put x=a.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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