Deriving the Equation for Area of a Ring

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The equation for the area of a ring is derived by calculating the difference between the areas of two circles, represented as π(R+dR)² - πR². This expression simplifies to an approximation for small dR, which is crucial in integral calculus. The approximation assumes that dR is vanishingly small, allowing for the neglect of higher-order terms. The discussion highlights the importance of understanding how differentials work in calculus. Thus, the area of a ring can be effectively approximated using this method for small changes in radius.
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How was the equation for area of a ring derived?
 

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I can derive the area as the difference of the areas of two circles. ##= \pi(R+dR)^2 - \pi R^2##
But I don't think this ##\pi (R+dR)^2 - \pi R^2## is equal to ## (2/pi R)(dR)## given in the beginning.
 
Calpalned said:
I can derive the area as the difference of the areas of two circles. ##= \pi(R+dR)^2 - \pi R^2##
But I don't think this ##\pi (R+dR)^2 - \pi R^2## is equal to ## (2/pi R)(dR)## given in the beginning.

No, but it's an approximation for small ##dR##.
 
When setting up integrals, the differential is assumed to be vanishing small, so that terms proportional to the powers of the differential can be neglected.
 
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