Deriving V-E Relation for Uniformly Charged Rod at Radial Distance r > a"

AI Thread Summary
To derive the relation between the electric potential V and the electric field E for a uniformly charged rod at a radial distance r greater than its radius a, Gauss' Law is applicable to find the electric field E. The electric field E can be expressed as E = λ/(2πε₀r), where λ is the linear charge density. The relationship between the electric field and potential is given by E = -dV/dr, which leads to the potential V being calculated through integration of E. The confusion arises from the interpretation of deriving a relation, as it involves understanding the fundamental connection between E and V. Ultimately, the derivation clarifies how potential varies with distance from the charged rod.
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Could someone help me out on this problem?

Derive a relation between the potential V and the magnitude of the Field E at a radial distance r from the axis
of a very long uniformly charged rod of radius a (r > a).
 
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I'm not following that properly. At first I would have thought you use Gauss' Law for electrostatics to work out the E field at a point r from the rod and then use E = -dV/dr, but that doesn't seem right :/.
 
I'm not sure what you mean by "derive a relation between..." since \vec E = -\nabla \Phi is fundamental.
 
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