Designing Shielding Box for High Voltage Cylinder

AI Thread Summary
The discussion focuses on designing a shielding box for a high voltage cylinder (+60kV) and calculating the necessary distance between the cylinder and a metal plate. Participants suggest using Gauss' law to approximate the box as a cylindrical capacitor if the distance is much greater than the radius. Numerical simulations are recommended as an alternative approach, with suggestions for using a two-dimensional grid and the Laplace equation to solve the potential distribution. Specific formulas for capacitance and references to relevant literature are provided for further guidance. The conversation emphasizes the importance of accurately modeling the electric field and potential in the design process.
india
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i have to design one shielding box. in that there is cylinder having high voltage +60kev. and box having metal plate. so i have to calculate the electric field on that cylinder and then decide , what should be the distance in between plate and cylinder. i have attach the geometry on the file. please see it.
 

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Could anyone help me ?
 
Can you use some approximation, like d>>R?
In that case, it should be possible to approximate the box as a cylinder, and calculate it like a cylindrical capacitor using Gauss' law (google should give you some ways to do this).

If not, a numerical simulation might be the easiest way to solve your problem.
 
yes, thanks ... bt i think i wl get that for cylindrical capacitor. bt right now i have another design.. bt i wl try for solving it.
btw what type of numerical solution that i should use??



mfb said:
Can you use some approximation, like d>>R?
In that case, it should be possible to approximate the box as a cylinder, and calculate it like a cylindrical capacitor using Gauss' law (google should give you some ways to do this).

If not, a numerical simulation might be the easiest way to solve your problem.
 
For a cylinder and one metal plate, the capacitance per unit length is given by Smythe Static and Dynamic Electricity 3rd edition page 78:
C=\frac{2\pi\epsilon}{cosh^{-1}\frac{h}{R}}
for cylinder of radius R with axis parallel to and at a distance h above an infinite plane. The problem of a cylinder between two conducting planes is given on page 105.
 
india said:
btw what type of numerical solution that i should use??
A two-dimensional grid, for example. Use your favourite tool, plug in the boundary conditions for the potential Φ (box and circle) and the Laplace equation \nabla^2 \Phi = 0 in the vacuum (or air, as good approximation).

In excel, the result can look like http://s7.directupload.net/file/d/2824/7fhjuxw8_jpg.htm (I did this for a cylinder over an infinite plane orthogonal to the cylinder axis, and it uses cylindrical coordinates).
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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