Determinant of a symmetric matrix

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SUMMARY

The determinant of a symmetric matrix can be simplified using specific vector definitions. In the case of the matrix A(x) defined as A(x) = \[ \left( \begin{array}{ccc} f(x) & a_{12}(x) & a_{13}(x) \\ a_{12}(x) & f(x) & a_{23}(x) \\ a_{13}(x) & a_{23}(x) & f(x) \end{array} \right)\], the determinant is expressed as f(x)^3 - B2f(x), where B = (a_{23}, a_{31}, a_{12}). The discussion also raises the question of how this determinant simplification can be generalized to n x n matrices.

PREREQUISITES
  • Understanding of symmetric matrices
  • Knowledge of determinants in linear algebra
  • Familiarity with polynomial functions
  • Basic concepts of vector notation
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  • Research the properties of determinants for symmetric matrices
  • Explore generalizations of determinants for n x n matrices
  • Study the application of eigenvalues in relation to symmetric matrices
  • Learn about matrix factorization techniques, such as Cholesky decomposition
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Mathematicians, students of linear algebra, and anyone involved in computational mathematics or numerical analysis will benefit from this discussion.

krindik
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Hi,

Is there a simplification for the determinant of a symmetric matrix? For example, I need to find the roots of \det [A(x)]
where
<br /> A(x) = \[ \left( \begin{array}{ccc}<br /> f(x) &amp; a_{12}(x) &amp; a_{13}(x) \\<br /> a_{12}(x) &amp; f(x) &amp; a_{23}(x) \\<br /> a_{13}(x) &amp; a_{23}(x) &amp; f(x) \end{array} \right)\]<br />

Really appreciate if you could point me in the correct directions. Thanks in advance,

Krindik
 
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Hi Krindik! :smile:

If we define a vector B = (B1, B2, B3) = (a23, a31, a12),

then the determinant is f(x)3 - B2f(x) :wink:
 
Thanks :)
 
tiny-tim said:
Hi Krindik! :smile:

If we define a vector B = (B1, B2, B3) = (a23, a31, a12),

then the determinant is f(x)3 - B2f(x) :wink:

How is this generalized to nxn matrices?
 

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