Determinant of a symmetric matrix

krindik
Messages
63
Reaction score
1
Hi,

Is there a simplification for the determinant of a symmetric matrix? For example, I need to find the roots of \det [A(x)]
where
<br /> A(x) = \[ \left( \begin{array}{ccc}<br /> f(x) &amp; a_{12}(x) &amp; a_{13}(x) \\<br /> a_{12}(x) &amp; f(x) &amp; a_{23}(x) \\<br /> a_{13}(x) &amp; a_{23}(x) &amp; f(x) \end{array} \right)\]<br />

Really appreciate if you could point me in the correct directions. Thanks in advance,

Krindik
 
Physics news on Phys.org
Hi Krindik! :smile:

If we define a vector B = (B1, B2, B3) = (a23, a31, a12),

then the determinant is f(x)3 - B2f(x) :wink:
 
Thanks :)
 
tiny-tim said:
Hi Krindik! :smile:

If we define a vector B = (B1, B2, B3) = (a23, a31, a12),

then the determinant is f(x)3 - B2f(x) :wink:

How is this generalized to nxn matrices?
 
Back
Top