Determination of Unknown Constants in Differential Equations

mtak0114
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What is the general rule for determining how many initial conditions one needs to uniquely determine a solution of a set of ODEs or PDEs?

is it simply the number of derivatives? How about for coupled differential equations?

cheers

M
 
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From what I understand you are correct, an equation with n derivatives requires n initial conditions. Not too sure if the same applies for coupled DEs though.
 
Generally speaking, and I mean as general as you can get, the number of initial conditions needed is equal to the order of the DE. Idk anything about PDE's but that rule holds true for all linear, homogeneous ODEs. Non-linear DEs often are unsolvable. It holds true for systems of ODEs, also.
 
HallsofIvy posted this in another forum:

The set of all solutions to any second order, linear, homogeneous, equation forms a vector space of dimension two. That means, if you can find two independent solutions (that form a basis for the space) you can write any solution as a linear combination of the two solutions. That's all y(x)= c_1y_1(x)+ c_2y_2(x) means.

You can take that beyond second order and say for all linear, homogeneous equations.
 
I guess my question is really in regards to a set of coupled differential equations, could you have a set of say N coupled nonlinear ODEs which have a unique solution without specifying any initial conditions?

cheers

M
 
No, solving a single nth order equation will involve n unknown constants. Solving, say, m nth order equations will involve mn unknown constants. More generally, if you have a system of m differential equations, each of order n_1, n_2, \cdot\cdot\cdot, n_m, the solution will involve n_1+ n_2+ \cdot\cdot\cdot+ n_m unknown constants that have to be determined by additional conditions.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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