Determine extinction coefficients in glass for Fe2+/Fe3+

Click For Summary

Discussion Overview

The discussion revolves around determining the extinction coefficients of Fe2+ and Fe3+ in glass, specifically within a soda-lime-silicate system. Participants are exploring the application of the Lambert-Beer law to analyze absorbance measurements and are encountering issues with negative extinction coefficient values.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Mark seeks to determine the extinction coefficients for Fe2+ and Fe3+ in glass using absorbance data and the Lambert-Beer law.
  • Mark has measured absorbance for two glasses with varying Fe2+/Fe3+ ratios and total iron concentrations.
  • Mark reports obtaining negative values for one of the extinction coefficients, which he finds nonsensical.
  • Chemisttree suggests solving for Fe3+ in terms of Fe2+ and total Fe, proposing a mass balance equation.
  • Mark expresses confusion about how to incorporate total Fe into his equations, questioning where it fits in the calculations.
  • Chemisttree reiterates the importance of the mass balance equation, but Mark feels it does not resolve his issue.
  • Mark shares concentration data for two glasses, noting that substituting values leads to unchanged results.
  • Another participant inquires about the values of the extinction coefficients used and whether they vary with wavelength.
  • Mark confirms that the extinction coefficients for both Fe2+ and Fe3+ vary with wavelength and that the unknowns in his equations are these coefficients.
  • Mark mentions that he will provide raw absorbance data later for further assistance.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to resolve the issue of negative extinction coefficients. Multiple viewpoints on how to incorporate total iron concentration into the calculations remain contested.

Contextual Notes

Participants note limitations in the current discussion, including the absence of raw data and the potential impact of varying extinction coefficients with wavelength on the results.

ACvub
Messages
9
Reaction score
0
Hello everybody,

I want to determine the extinction coefficients of Fe2+ and Fe3+ in glass.
There are literature data (e.g. Weyl's book "coloured glass"), so I know what kind of curves I should expect. As I am studying a slightly different soda-lime-silicate system, I want to recalculate the curves.

I have glasses with different Fe2+/Fe3+ ratio and total iron concentration [Fe].
I have measured the absorbance of two glasses and I have solved a simple two equations system starting from Lambert-Beer law: A = Ʃ εCd
where A is absorption, ε is the extinction coefficient, C is the concentration and d is the thickness of my glass.

Unfortunately, I get negative values in one of the two extinction coefficient curves. Obviously, this doesn't make sense.

Anyone sees what is wrong in my reasoning? I can't figure it out.

Thank you very much in advance,
Mark

PS For a close look at the system I have made, see the attachment (.pdf)
 

Attachments

Chemistry news on Phys.org
Try solving for Fe+3 in terms of Fe+2 and total Fe.
 
Thank you chemisttree for replying.
However, I don't get what you mean. How can I solve in terms of total Fe?
In the system I have the concentrations of the two absorbing species:
Fe3+ (CFe3+) and Fe2+ (CFe2+)

Where should total Fe appear in the equations?
 
You said you know total Fe for the glass, so you can write an equation for the mass balance:

Fe2+ + Fe3+ = Ftotal
 
You are right! I understand.
But even if I substitute CFe3+ with (CFetotal - CFe2+), I don't see how it would solve the problem. At the end it is always the same value.
 
the unknown variable are the ε for the two ionic species.
so adding the mass balance equation does not add any value.
 
Sooo, you're not even going to try it my way?
 
I am sorry chemisttree, maybe I hadn't explain well myself. I didn't want to be disrespectful.
I have tried to use your advice. But I don't see how.
Substituting ferric concentration with the subtraction of ferrous from total iron concentration, the final solution remain unchanged.

I attached the spectra of the two glasses I am using. Also, I have plot quickly (read as "I haven't add units and axis names") the absorption coefficients I obtained for Fe2+ and Fe3+. You see that εFe3+ is negative, which doesn't have any physical meaning.

Below you find the concentration data for both GlassA and GlassB.

GlassA:
CFe2+ = 0.056 wt%
CFe3+ = 0.125 wt%
CFetotal = 0.181 wt%

GlassB:
CFe2+ = 0.127 wt%
CFe3+ = 0.285 wt%
CFetotal = 0.412 wt%

If I substitute in GlassA CFe3+ = CFetotal - CFe2+, I get the same value: 0.181 - 0.056 = 0.125 wt%.

I would appreciate if you could keep helping me.
Thank you.
 

Attachments

  • GlassAbsorbances.PNG
    GlassAbsorbances.PNG
    6.2 KB · Views: 1,174
  • GlassExtCoeff.PNG
    GlassExtCoeff.PNG
    7 KB · Views: 839
Nobody has an idea on what's wrong?
 
  • #10
For the attached spectra, what value of extinction coefficient did you use for Fe+2 and Fe+3? Did you hold the extinction coefficient for Fe+2 constant? Or did it vary with wavelength?
 
  • #11
they both vary with wavelength. In the 2-equations system I have attached to my first thread, the unknowns are the two extinction coefficients.
 
  • #12
So you have the spectra in the form of wavelength and absorbance? Can't help you without raw data.
 
  • #13
Yes, my data are absorbance as a function of wavelength. NOw I don't have access to the hard drive where data data are. I will post the raw data later on today so you can have a look.
thank you again!
 
  • #14
sorry for the delay. here is the file with the absorbance for both glasses.
 

Attachments

Similar threads

  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 11 ·
Replies
11
Views
2K