Determine image distance relative to lens

AI Thread Summary
Two identical diverging lenses, each with a focal length of -6.5 cm, are separated by 13 cm, with an object placed 3.0 cm to the left of the left lens. The initial calculations using the lens formula yielded an image distance of -0.487 cm for the first lens. The subsequent calculations for the second lens, using the image distance from the first lens, produced an incorrect final image distance of -4.386 cm. There is uncertainty about whether to use -13.487 cm or -12.547 cm for the second lens calculation. The discussion emphasizes the need to verify calculations and clarify the correct approach to find the final image distance relative to the right lens.
phys62
Messages
53
Reaction score
0

Homework Statement


Two identical diverging lenses are separated by 13 cm. The focal length of each lens is -6.5 cm. An object is located 3.0 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right.


Homework Equations


1/i + 1/o = 1/f

1/i = 1/f - 1/o

The Attempt at a Solution


1/i = 1/-6.5 - 1/3
i= -.487

13 + .487 = 13.487 cm

I feel like I'm not doing this right at all.. can someone please let me know if I'm even on the right track?
 
Physics news on Phys.org
13 + .487 = 13.487 cm
This is the object distance for the second lens. Find the final image distance from the second lens.
 
Ok so I took 1/13.487 + 1/i = 1/-6.5

and I solved for i and got -4.386 cm.

Is this correct, or should I have used -13.487 and got -12.547 as my answer?
 
and I solved for i and got -4.386 cm.
This is correct.
 
It's telling me that answer is incorrect.. I guess I'll try the -12.547 next
 
1/i = 1/-6.5 - 1/3
i= -.487

Check this calculation.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top