What is the normal force exerted on a suitcase being pulled at an angle?

AI Thread Summary
To determine the normal force on a suitcase being pulled at an angle, the mass of the suitcase is 20.0 kg, and Dylan exerts a force of 100 N at a 30° angle above the horizontal. The gravitational force acting on the suitcase is calculated as Fg = mg = -196.2 N. Using the equilibrium condition for vertical forces, the normal force (Fn) is found by balancing the forces: Fn - 196.2 N + (100 N)sin(30°) = 0. The resulting normal force exerted by the floor on the suitcase is 146.2 N upward.
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Homework Statement


Dylan is rushing to catch a flight. As he walks in the airport he pulls his suitcase behind him, which is rolling on its wheels. The mass of the suitcase is 20.0kg. Dylan pulls on the handle so that he exerts a force on the handle of 100N, 30° above the horizontal. Determine the normal force exerted by the floor on the suitcase.

Given:
m=20.0kg
FaDS (applied force Dylan on suitcase)= 100N
Degree= 30° above horizontal

Homework Equations


Fg= mg
Total force in the y = 0 in mechanical equilibrium
Fnet=ma

The Attempt at a Solution


Fg= mg= (20.0kg)(-9.81m/s/s)=-196.2N
Total force in the y is 0, therefore, Fn+Fg+Fay=0
This means, Fn-196.2N+ (100N)sin30°=0
Fn= 146.2N upward = +146.2N
 
Last edited:
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Yes, that looks correct.
 
Thank you!
 

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