Determine the intensities of GaAs crystal planes

ralden
Messages
76
Reaction score
0
GaAs crystal structures have basis atoms:

Ga: (0 0 0), (0.5 0.5 0),(0.5 0 0.5),(0 0.5 0.5)
As: (0.25 0.25 0.25),(0.75 0.75 0.25),(0.75 0.25 0.75),(0.25 0.75 0.75)

i'm trying to find intensities at all of its plane, using this equation:

I = (F^2)*m*Lf (m= multiplicity, Lf=lorentz factor)

where F = f*cos(2*pi*(hx +ky +zl)), (f =atomic scattering factor)

or you could used:the simplest form:
F^2 = 16(fGa^2 + fAs^2 + 2f*Ga*fAs*(cos(90*(h+ k +)l)) )

but using this equation you would have peaks at 001 plane and other planes that base on literature would generate a zero Intensity,

so my problem was, are my equations or the F^2 simplest form are correct?
 
Physics news on Phys.org
GaAs is FCC, so (100) peaks are forbidden.

With such structure factor formulae, it is always assumed that the peak exists to begin with. Otherwise you could calculate a non-zero structure factor even for non-integer values of hkl - which clearly do not give a Bragg peak.
 
Hi. I have got question as in title. How can idea of instantaneous dipole moment for atoms like, for example hydrogen be consistent with idea of orbitals? At my level of knowledge London dispersion forces are derived taking into account Bohr model of atom. But we know today that this model is not correct. If it would be correct I understand that at each time electron is at some point at radius at some angle and there is dipole moment at this time from nucleus to electron at orbit. But how...
Back
Top