Determine the magnitude of the normal force exerted by the table.

AI Thread Summary
To determine the work done by the applied force on a 2.00 kg block pushed along a frictionless table, the formula W = Fcos(theta) * delta X is used, but the calculated answer of 37.1 joules is not accepted by the class website. The issue may stem from the angle used in the calculation or the interpretation of the force components. For part b, the normal force exerted by the table needs to be calculated, considering the vertical components of the applied force. The discussion highlights the importance of accurately resolving forces and understanding the physics principles involved. Clarification on the calculations and methodology is essential for correct problem-solving.
Lilly
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hi,
i need some help w/ this problem:
a) A block of mass 2.00 kg is pushed 2.32 m along a frictionless horizontal table by a constant 17.7 N force directed 25.5 degbelow the horizontal. Determine the work done by the applied force.
b) Determine the magnitude of the normal force exerted by the table.

For part a i used the formula W= Fcos(theta) delta X and i keep coming up with the answer 37.1 joules. It's not right though, and i don't know what I'm doing wrong. help please. thanks. lilly
 
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It looks right to me. What makes you think it's wrong?
 
it's wrong because there is this website for my physics class where we have to post our answers to the questions and it won't accept an answer unless its right. and my answer is not being accepted, so it must be wrong...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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