Determining arm length of catapult

AI Thread Summary
To determine the arm length of a catapult designed to launch a 2-gram ping pong ball 1.5 meters using a 3/4" paper clamp as the energy source, focus on the principles of torque and angular acceleration. The catapult operates as a first-class lever, with the fulcrum positioned in the middle. The key is to calculate the tangential speed of the arm rather than centripetal acceleration, as this relates directly to the required launch distance. Understanding the relationship between torque and the arm length is crucial for accurate calculations. Properly applying these physics concepts will enable the successful design of the catapult.
ArrowHeart
Messages
3
Reaction score
0
Hi, I have a big problem...
I got a project on building a catapult. Easy, right? WRONG! We are supposed to determine the arm length without trial and error and I have no clue what to do. Please please help!

Catapult is supposed to be built with 3/4" paper clamp as the only energy source and it must project a 2gram pingpong ball 1.5m. The catapult is a classic 2nd class lever. How would I calculate the arm length?
 
Physics news on Phys.org
It's all about torque.
 
ArrowHeart said:
The catapult is a classic 2nd class lever. How would I calculate the arm length?
Don't you mean a 1st class lever? A catapult has the fulcrum in the middle.

AM
 
Sorry, I mis-typed it. It is a first class lever.
How it is torque related? I tried to determine the centripetal acceleration, it didn't work out very well -_-'
 
Last edited:
ArrowHeart said:
How it is torque related? I tried to determine the centripetal acceleration, it didn't work out very well -_-'
You don't need to worry about centripetal acceleration. You are concerned about the tangential speed of the arm, which is a function of the angular acceleration or torque.

AM
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top