Determining Clockwise & Counterclockwise Torque: Help Needed!

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To determine clockwise and counterclockwise torque, identify the forces acting on the object and their respective distances from the pivot point. Counterclockwise torques are generated by forces that cause rotation in a counterclockwise direction, while clockwise torques result from forces that cause clockwise rotation. The calculation involves multiplying the force by the distance from the pivot point for each force. The discussion emphasizes visualizing the forces and their effects on rotation to understand the torque direction. Understanding these concepts is crucial for solving torque-related problems effectively.
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Please HELP!Torque Problem?

I have no idea how to do this! My teacher never really showed us how to determine clockwise and counterclockwise torque. Any help would be greatly appreciated!

Referring to the diagram(I have attached it):
1. Which forces create counterclockwise torques and calculate the sum of these torques.
2. Which forces create clockwise torques and calculate the sum of these torques.

I forgot to add Xo=.4610m

This is probably very simple, but I don't have a clue! Thanks!
 

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Please help, I added the missing Xo. How do you know if it clockwise or counterclockwise?
 
This was almost exactly like a problem I had on my provincial exam last year.

Depending on where you put the...jesus...whatever the triangle thing is called...the forces to the left are counter clockwise torques and to the right are clockwise torques. Think of the force pulling the beam down and the beam rotating in a C or CC motion. That's how I always thought about it.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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