Determining non-conserved work from a collision

  • Thread starter Thread starter JoeyBob
  • Start date Start date
  • Tags Tags
    Collision Work
AI Thread Summary
The discussion focuses on calculating non-conserved work during a collision, emphasizing that kinetic energy is not conserved due to momentum transfer. The initial kinetic energy is noted as 94.556, with potential energy being zero. Participants clarify that during a collision, kinetic energy can be lost, and the final velocity, calculated using conservation of momentum, is 3.075. This final velocity allows for the determination of changes in kinetic energy and work done. It is suggested that solving the problem algebraically before substituting values can simplify the process.
JoeyBob
Messages
256
Reaction score
29
Homework Statement
see attached
Relevant Equations
W=change in kinetic energy
So I know from a previous part of the problem that the kinetic energy right before the collision is 94.556.

The non conserved work would also equal the change in kinetic energy + change in potential energy.

What I don't understand is how the potential or kinetic energy would change during the collision. The potential energy is already 0 and wouldn't the kinetic energy just be transferred (so the object would slow down because its heavier).

answer is suppose to be -47.32
 

Attachments

  • wquestion.PNG
    wquestion.PNG
    13 KB · Views: 128
Physics news on Phys.org
JoeyBob said:
wouldnt the kinetic energy just be transferred
Never assume work is conserved without good reason. In a coalescence, as here, you can use conservation of momentum to find the new speed, and you will see that KE has been lost.
 
haruspex said:
Never assume work is conserved without good reason. In a coalescence, as here, you can use conservation of momentum to find the new speed, and you will see that KE has been lost.
So from conservation of momentum I find that the final velocity was 3.075, which gives a final kinetic energy, which allows me to calculate the change, which let's me find the work.
 
JoeyBob said:
So from conservation of momentum I find that the final velocity was 3.075, which gives a final kinetic energy, which allows me to calculate the change, which let's me find the work.
Yes, but it is much better, for several reasons, to solve a problem purely algebraically, only plugging in numbers at the very end. Had you done that, you would have found it was unnecessary to find the velocities, neither before impact nor after.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top