Determining Oxidation Numbers of KClO3, NH4+, Cr2O72-, MnO42-

AI Thread Summary
The oxidation numbers for KClO3, NH4+, Cr2O72-, and MnO42- were discussed, focusing on the calculation methods. In KClO3, chlorine has an oxidation state of +5, derived from potassium's +1 and oxygen's -2 contributions. The discussion emphasized using established rules for determining oxidation states, such as the neutrality of the molecule and the known oxidation states of other elements. Participants shared their calculations and clarified the reasoning behind the oxidation states. Understanding these principles is essential for accurately determining oxidation numbers in various compounds.
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Determine the oxidation numbers of the underlined elements in the following formulas:?
If you could explain each one, it would be greatly appreciated. Thanks!
a) KClO3
b) NH4+
c) Cr2O72-
d) MnO42-
 
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Okay is a) +5 because K=+1 and O=-2? I'm just wondering cause someone posted that on yahoo.
 
Yep, Cl in KClO3 is +5 (regardless of what was posted on Yahoo).

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do you think you could explain to me why?
 
Because it can be calculated following rules from the page I have linked to?

Nothing magic about it. Molecule is neutral, K is +1 (one of the rules), O is -2 (one of the rules), so Cl+1+3*(-2)=0.

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methods
 
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