How Do You Calculate Peak Current for a Light Bulb?

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To calculate the peak current for a light bulb using 75 watts of power at an RMS voltage of 110 volts, the electrical resistance of the filament is determined to be 161.3 ohms. The relationship between RMS voltage and peak voltage is crucial, as the peak voltage can be calculated using the formula V_peak = V_rms × √2. Once the peak voltage is established, the peak current can be found using Ohm's law (I_peak = V_peak / R). The final peak current is approximately 0.954 A. Understanding these relationships and equations is essential for accurate calculations.
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[SOLVED] Determining Peak Current

Homework Statement



A light bulb uses 75 watts of power when a lamp is plugged into a wall socket (RMS voltage = 110 volts alternating at a frequency of 60 hertz)

Determine the electrical resistance of the light bulb filament.

Determine the peak current.

Homework Equations



f = 1/T - I=V/R - P=IV

The Attempt at a Solution



I determined the electric resistance to be 161.3 ohms. However, I don't know how to determine the peak current. Can someone please help?
 
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Someone please help. I know that the answer is 0.96 A.

I just don't know how to get to this solution and what equation to use.
 
If you know the rms voltage, you can find the peak voltage. What's the relationship between the two? Then from that you can find the peak current since you now know the resistance of the bulb.
 
Okay, I got the answer (actually it is .954 A). Thank you very much.
 

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