Determining Shear Stress on Flexible Vegetation

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To determine the shear stress on a plant when pulled perpendicular to its length, the cantilever beam equation can be applied, but with specific boundary conditions depending on the force application point. The Young's modulus and moment of inertia are crucial for accurate calculations, and the bending energy can be derived from the curvature along the plant's length. If the pulling force is applied at different locations, the boundary conditions will need to be adjusted accordingly. Engineers often utilize finite element analysis software for these complex calculations. Understanding these principles is essential for accurately assessing the mechanical behavior of plants under stress.
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I want to know how to determine the shear stress a plant undergoes when it is pulled perpendicular to the plant length and then bends in the direction you are pulling. Would I use a cantilever beam equation? What if the force pulling the plant is at different locations along the length of the plant (i.e. if I pulled at the base vs. pulling at the top)? Or at many places at once?
 
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Welcome to PF, Czarnm.
Going by the title of the thread, I was expecting a conversation about rubber trees. Since that's not the case, I'm afraid that I have nothing to contribute.
 
Sure- you could use the cantilever equation (with caveats):

EI\frac{\partial^{4}y}{\partial s^4} = 0

Where E is the Young's modulus, I the moment of inertia, 's' the coordinate that deforms with the beam, etc. etc.

You probably want to start with a free end and a built-in end for the boundary conditions- the fixed end position and slope are zero, the bending moment at the free end vanishes, and the force 'F' is applied at the free end as well:

y(0) =\frac{\partial y}{\partial s}\right)_{s=0} = 0

\frac{\partial^{2} y}{\partial s^{2}}\right)_{s=L} = 0

\frac{\partial^{3} y}{\partial s^{3}}\right)_{s=L} = F

If you are applying a force at different locations, your boundary conditions will change as well.

In order to extract out the shear stress, I think you need to be careful- one could calculate the bending energy by calculating the curvature along the length, for example.

In any case, you need to know Young's modulus which is experimentally determined.

Basically, this is why engineers have moved to finite element analysis software platforms to calculate all this stuff for them.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks

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