Determining the cartesian equations

  • Thread starter Thread starter shawns
  • Start date Start date
  • Tags Tags
    Cartesian
shawns
Messages
1
Reaction score
0

Homework Statement



determine the cartesian equation of the plane that contains the following lines:
L1: r= (4,4,5) + t(5,-4,6)
L2: r= (4,4,5) + s(2,-3,-4)

Homework Equations



I kno I'm supposed to use the equation Ax + By + Cz + D. but i don't know how to use it with this type of problem

The Attempt at a Solution



Don't understand it at all :S
 
Physics news on Phys.org
Two lines can be contained in a plane if and only if,

a) The lines are parallel, or
b) The lines intersect

Hint: The direction vectors of each line should indicate whether they are parallel or not

Does that help?
 
Last edited:
shawns said:

Homework Statement



determine the cartesian equation of the plane that contains the following lines:
L1: r= (4,4,5) + t(5,-4,6)
L2: r= (4,4,5) + s(2,-3,-4)

Homework Equations



I kno I'm supposed to use the equation Ax + By + Cz + D. but i don't know how to use it with this type of problem
Ax + By + Cz + D is NOT an equation. The equation you're thinking of is Ax + By + Cz + D = 0.
shawns said:

The Attempt at a Solution



Don't understand it at all :S

You are given a point in the plane and two vectors that are in the plane. You need to work with the two vectors to find a third vector that is perpendicular to the plane.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top