- #1
Tricky557
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Determining what value "y" will approach eventually
I'm having a bit of trouble with an equilibrium problem. The autonomous equation given is:
y' = (2y+8)(y-3)(y-8)^3
The first task is to find and classify the stability of each equation, which I've done.
Points: y=-4, y=3, y=8
The bit that I am unsure of how to do comes next.
a.) If y(8) =-10, to what value will y approach eventually?
b.) If y(-4) = 8, to what value will y approach eventually?
I've seen it done with direction fields, but I've never really understood those.. I've also heard that there is a way to determine what value y will approach without actually solving the differential equation.
Can anyone help?
I'm having a bit of trouble with an equilibrium problem. The autonomous equation given is:
y' = (2y+8)(y-3)(y-8)^3
The first task is to find and classify the stability of each equation, which I've done.
Points: y=-4, y=3, y=8
The bit that I am unsure of how to do comes next.
a.) If y(8) =-10, to what value will y approach eventually?
b.) If y(-4) = 8, to what value will y approach eventually?
I've seen it done with direction fields, but I've never really understood those.. I've also heard that there is a way to determine what value y will approach without actually solving the differential equation.
Can anyone help?