Diamond Ring in Front of a Convex Lens?

AI Thread Summary
A 1.5 cm high diamond ring is positioned 20 cm in front of a convex lens with a 30 cm radius of curvature. The focal length can be approximated using the lens maker's formula, assuming a double convex lens, leading to f = R/2. The user initially struggled with the problem due to the lack of information about the focal length. After clarification, it was revealed that the teacher intended to refer to a mirror instead of a lens, resolving the confusion. Understanding the correct optical element is essential for accurately determining the image position, size, and magnification.
itsgood819
Messages
3
Reaction score
0

Homework Statement



A 1.5 cm high diamond ring is placed 20 cm in front of a convex lens whose radius of curvature is 30 cm.

a) What is the position and the size of the image?
b) What magnification does this lens have?

Homework Equations



1/f= 1/di + 1/do
m= -di/do or hi/ho

The Attempt at a Solution



the 20 cm is do, and the ho is 1.5 cm. Since it's a lens, I don't know the focal length. I tried using the 1/f= 1/di + 1/do, but I don't any variable besides the do.

How would I solve this problem? Help please, and thank you! Also, I'm new to this forum so my posting might look a bit weird.
 
Physics news on Phys.org
Is it a double convex lens with both sides having the same radius of curvature? If so, you can use the lens maker's formula to figure out the focal length.
 
Because, the index of refraction of the lens material is not given, I would assume that f=R/2.
 
thank you for your suggestions! it turns out that my teacher actually meant to put mirror instead of lens.
 
itsgood819 said:
it turns out that my teacher actually meant to put mirror instead of lens.
Aha! Now the problem makes sense. :wink:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top