Did I put this truth table in the k-map correctly?

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The discussion centers on verifying a Karnaugh map (K-map) setup based on a provided truth table. The original poster expresses confusion due to receiving different answers after multiple attempts. A participant identifies an error in the K-map, noting discrepancies in the representation of variables, specifically regarding the entries for c'. They suggest a simplified boolean expression and point out a mistake in the K-map where AB'C' should be AB'C. The conversation emphasizes the importance of accuracy in K-map entries to achieve the correct simplification.
mr_coffee
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Hello everyone, I need to you to check if i did this right, i did this k-map 3 different times and everytime i do it, i get a different answer. okay here is the picture:
http://img212.imageshack.us/img212/109/lastscan3ga.jpg

also here it is at another location:
http://show.imagehosting.us/show/772450/0/nouser_772/T0_-1_772450.jpg
Thanks.
 
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no, you have an error. you have two c' entries on thr map but only one in the original truth table.
 
so the 1's should be here:
011
101
111
110
right?>
 
You could simplify using boolean theorems to check your answer.

z= A'BC+AB'C+ABC'+ABC

The last term ABC, has at least two variables common in the other terms.

Z = A'BC+ABC+AB'C+ABC+ABC'+ABC
Z = BC(A'+A) + AC(B'+B) + AB(C'+C)
Z = BC + AC + AB

You have BC + AC' + ABThe mistake that you made in the K-map is that you have AB'C' instead of AB'C.
 
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