DIFFEQ - Discontinuous Forcing Functions (should be an easy question)

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Ok, we just started this chapter, and I am slightly confused with one specific aspect of the info... I'll just go through an example, it's the best way to explain it IMHO.
I have to find the Laplace transform of the following function.
The table of transforms that I can use are (sorry about the formatting, I know they are not equal to each other):
u_c(t) = \frac{e^{-cs}}{s}
u_c(t)f(t-c) = e^{-cs}F(s)
t^n = \frac{n!}{s^{n+1}}

f(t)= is defined as a system of equations (sorry I don't know the LaTeX formatting for it).
f(t)=0|t<1
f(t)=t^2-2t+2|t\geq1

So f(t) can be rewritten as:
f(t) = u_1(t)(t^2-2t+2)

Ok, so now this is where I get confused. I have to do the Laplace transform of f(t) = u_1(t)(t^2-2t+2. But the only table value I have is:
u_c(t)f(t-c) = e^{-cs}F(s)

But, this doesn't actually match what I have. Since, f(t) is not of the form f(t-c). So if anyone could just explain this part better to me... that would be awesome. My thought process here is that I have to change f(t-c) to be f(t).
So:
(t-1)^2 = t^2-2t+1
(t-1)^2 +1 = f(t)
This would allow me to use the rule right?

So I would then have:

F(s) = e^{-cs}/s L((t-1)^2+1) = e^{-cs}/s [L(t^2)+L(-2t)+L(2)]

Is this idea even right? I guess I just don't understand what is really going on here.
On a second note what the hell is going on with the latex formatting? Is anyone else having troubles previewing their changes?
 
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Nevermind

Nevermind... I figured it out. Thanks though :)
If anyone wants to elaborate, be my guest.
 
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