Difference between Position Vector & Displacement Vector? (no calculatins)

AI Thread Summary
The position vector represents a specific point in space defined by coordinates, such as (x, y) or (x, y, z), without indicating direction. In contrast, the displacement vector quantifies the difference between two points in space, incorporating both magnitude and direction. While a position vector can be viewed as a displacement vector relative to an arbitrary origin, it does not possess direction itself. The distinction lies in the fact that the position vector identifies a location, whereas the displacement vector describes a change in position. Understanding these differences is crucial for clarity in vector analysis.
LearninDaMath
Messages
295
Reaction score
0
Difference between "Position Vector" & "Displacement Vector?" (no calculatins..)

http://en.wikipedia.org/wiki/Position_(vector )

http://en.wikipedia.org/wiki/Displacement_(vector )


Is the position vector simply an initial vector given by coordinates (x,y) or (x,y,z) such as (8,4) or (8,4,5)..

While the displacement vector is simply the difference between two given vectors on an xy or xyz plane, such as Vector A minus Vector B representing (\stackrel{9}{5}) - (\stackrel{5}{10}) minus Vector C, being (\stackrel{4}{-5}) ..with Vector C being the Displacement Vector?


P.S. The numbers in the second paragraph are supposed to be vector columns. I tried to create them using the "stack" function under "above and below" in the Latex Reference menu.
 
Last edited by a moderator:
Physics news on Phys.org


A vector has a magnitude and direction. A position has no direction, but only occupys space. A displacement vector is in fact the difference between points in space occupying more than a single point with a magnitude and direction.
 


Yep.
Note that a position vector is also a displacement vector relative to an arbitrary origin.


In latex you can write vectors like
Code:
\begin{pmatrix} x \\ y \end{pmatrix}
which looks like:
$$\begin{pmatrix} x \\ y \end{pmatrix}$$

Some people prefer:
$$\begin{bmatrix} x \\ y \end{bmatrix}$$
 


Thanks, I like Serena, for the confirmation and the Latex notation help. Much appreciated!.

clesling, I think there is some confusion between "position" and "position vector." One is a point in space with no magnitude or direction and the other is a displacement between a point in space and an arbitrary origin. I am now confident that is correct :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top