- #1
Larrytsai
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Homework Statement
y[n] - (2/3)y[n-1] = x[n]
what is y[n] if x[n] = diracdelta[n]
The Attempt at a Solution
for some reason, i argued that y[n-1] = diracdelta[n-1]
so
y[n] = diracdelta[n] + (2/3)diracdelta[n-1]
Im pretty sure this is wrong, anybody can help?