Difference Equation and Dirac Delta

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SUMMARY

The discussion centers on solving the difference equation y[n] - (2/3)y[n-1] = x[n] with x[n] defined as the Dirac delta function, diracdelta[n]. The correct solution is established as y[n] = (2/3)^{n}U[n], where U[n] represents the unit step function. The initial assumption that y[n-1] equals diracdelta[n-1] is identified as incorrect, leading to the need for clarification on deriving the correct solution.

PREREQUISITES
  • Understanding of difference equations
  • Familiarity with the Dirac delta function
  • Knowledge of the unit step function U[n]
  • Basic concepts of discrete-time signals and systems
NEXT STEPS
  • Study the properties of the Dirac delta function in signal processing
  • Learn about solving linear difference equations
  • Explore the relationship between difference equations and discrete-time systems
  • Investigate the role of the unit step function in signal analysis
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Students and professionals in electrical engineering, signal processing, and applied mathematics who are working with discrete-time systems and difference equations.

Larrytsai
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Homework Statement



y[n] - (2/3)y[n-1] = x[n]

what is y[n] if x[n] = diracdelta[n]


The Attempt at a Solution



for some reason, i argued that y[n-1] = diracdelta[n-1]

so

y[n] = diracdelta[n] + (2/3)diracdelta[n-1]

Im pretty sure this is wrong, anybody can help?
 
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The answer is y[n] = [itex](\frac{2}{3})^{n}[/itex]U[n]
 
You mind explaining how you got to what y[n] is?
 

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