Different dielectric material with different relative permittivity

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Different dielectric materials with varying relative permittivity affect capacitance when placed together, such as in concentric spheres filled with dielectrics A and B. The capacitance can be calculated using the formula C = ε₀ εᵣ A/d, where the voltage remains constant. When the dielectric is altered, such as when one plate of a capacitor pulls away, the effective capacitance decreases due to the increased gap, resembling two capacitors in series. The overall permittivity can be determined using the formula E = E1·E2/(E1 + E2). The presence of a conductor at the interface of the two dielectrics does not significantly impact the overall behavior as long as it is very thin.
FourierX
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I am wondering how to different dielectric material with different relative permittivity behave when put together. Say i have two concentric sphere and the space between them is filled with a dielectric of relative permittivity A from the outer surface of the inner sphere to the mid point between the inner and outer sphere and another dielectric of relative permittivity B fills the remaining space between the spheres. In such case, how do they behave and affect the capacitance of such a capacitor?
 
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The voltage between the plates remains, unchanging, the capcitance is calculated by, C_{ca} = {\epsilon}_0 {\epsilon}_r \frac {A}{d}. This in fact happens in real life, when capacitors are heated and one of the two plates in a parallel plate capacitor pulls away from the dielectric, another dielectric, air, fills in the gap. The capacitance is of course, reduced, but not only because of the greater gap.
 


I think it is like 2 separate capacitors (of half the spacing) in series. So the overall permittivity is the product / sum of the individual permittivity. In other words the presence of a conductor at the interface of the two dielectrics would have no effect as long as it was vanishingly thin.

E = E1.E2/E1 + E2
 
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