Different equations for Electric Energy, me understand

AI Thread Summary
The discussion clarifies the difference between two equations related to electric energy. The first equation, U=E/Q, describes the potential energy of a charged particle in an external electric field, while the second equation, E=(QU)/2, pertains specifically to the energy stored in a capacitor. The confusion arises because both involve charged plates, but they refer to different contexts: one for a particle and the other for a capacitor's stored energy. The second equation is derived from the first by considering the work done to move a small charge within the capacitor. Understanding this distinction helps clarify the concepts of electric potential energy and stored energy in capacitors.
Armand1
Messages
2
Reaction score
0
I've been reading recently about Electric Potential Energy and when introduced with the following situation of two charged plates (one (-) and the other (+)) and a charged particle between them I've been taught the following equation.

a) U=E/Q ⇔ E=QU

However now when I'm reading about a capacitor the equation for the stored electric energy in the capacitor is

b) E= (QU)/2

But how is this possible? A capacitor is to my understanding exactly what I've described above, two charged plates. So how come there is a different equation for the same thing?

For references I've read equation a) in Heureka A page 215 and b) in Heureka B page 180. The books are written in Swedish. I am very grateful for any help I can get to help me understand.

P.S I've been searching for the same question without luck so I believe it was appropriate to post this thread
 
Physics news on Phys.org


These two equations do not describe the same thing. The first one describes the potential energy of some particle (of charge Q) in some external electric field. The second describes the energy stored in a capacitor; Q is the charge stored in that same capacitor, not of some unrelated particle.
 


Thanks voko, I think i got it!
 


Very well. Keep in mind, though, that the second equation is obtained from the first one. It is done by considering some small charge dq that has to be moved from one plate to another. Assuming that the capacitor already holds some charge q, the potential difference is u = q/C; the energy required to move the small charge dq from one plate to another is then dE = u dq = q dq/C; this is the first equation. Integrating this we obtain E = Q^2/(2C) = QU/2.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top