Different way to solve projectile motion components?

AI Thread Summary
The discussion focuses on solving projectile motion components using given values for initial height, horizontal distance, and time. The user is attempting to derive equations for the initial velocity (v_0) and launch angle (Θ) but is confused by having multiple unknowns. They initially derived two equations based on horizontal and vertical motion but are unsure about the vertical component and the necessity of a maximum height value. After some clarification, they adjusted their calculations but still seek confirmation on their approach and values. The conversation highlights the complexities of projectile motion analysis and the importance of correctly identifying variables.
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Different way to solve projectile motion components?

Homework Statement


solve projectile motion formulas for \Theta and v_0
all measurements are in m, t is seconds
y_0=.005
x_0=0
the averages from my trials were:
x=8.775 m
t=1.3 s

Homework Equations


x=x_0+v_0*cos\Theta*t
y=y_0+v_0*sin\Theta*t+.5a_yt^2

The Attempt at a Solution


after plugging in my numbers gives:
for x
6.75=v_0*cos\Theta
which as far as I can see still has two unknowns, where do I go from here?

I'm pretty confused about the y component because I'm not even sure what y is supposed to be. Don't I need a y(max) number first?
 
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You don't need ymax necessarily.

What is y when t=1.3s and x=8.775m?
 


Alright, so I got some more insight from my roommate and managed to boil the equations down to:
6.75=v_0Cos\Theta
and
8.28=v_0Sin\Theta

am I headed in the right direction by then solving the x component for v_0=Cos\Theta and then combining it with the y formula to get something like 8.28=6.75Tan\Theta?

BTW I gave the wrong number for y_0. It should be .0125 m. if you are actually checking my work
 


Looks like you're on the right track, though I'm not sure where 8.28=v_0Sin\theta comes from.
 


does 6.37=v_0Sin\theta sound better?
 


Since I don't know what y is, I don't know.

Welcome to PF, by the way.
 
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