Different ways of solving for x in trig. equations

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The discussion centers on solving trigonometric equations and clarifying misconceptions about trigonometric identities. It emphasizes that cos(nx) does not equal n*cos(x), which is crucial for correctly solving equations involving multiple angles. The distinction between sin^2(x) and sin(2x) is highlighted, where sin^2(x) represents the square of sin(x), while sin(2x) refers to the sine of double the angle. Additionally, placing a coefficient in front of sin(x) affects amplitude, while placing it in front of the angle affects frequency. Understanding these differences is essential for accurately solving trigonometric problems.
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Homework Statement


According to my math book, I solved the following trig equation correctly:
1)
cos3x=0,500=
3x = 60° + n360°
x=20+n120°

2)I also solved this problem correctly:
4sin^2x -3sin^x= 0
sinx(4sinx-3)=0
x=n*360°
or
4sinx=3
sinx=3/4
x= ca. 49°
x=49° + n360° or 131+ n360°.

Now I´m wondering why I can´t solve question nr 1) in the following way:
cosx = 0,500/3
x=80°
x=80° + n360°

i.e. why can´t I solve question nr 1 the way I did question nr 2?
I was also wondering if sin2x is the same as 2sinx? does it make a difference where I place the 2?

Homework Equations



NA

The Attempt at a Solution



see above
 
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Attis said:

Homework Statement


According to my math book, I solved the following trig equation correctly:
1)
cos3x=0,500=
3x = 60° + n360°
x=20+n120°

2)I also solved this problem correctly:
4sin^2x -3sin^x= 0
sinx(4sinx-3)=0
x=n*360°
or
4sinx=3
sinx=3/4
x= ca. 49°
x=49° + n360° or 131+ n360°.

Now I´m wondering why I can´t solve question nr 1) in the following way:
cosx = 0,500/3
x=80°
x=80° + n360°

Because (in general) ##\cos nx \neq n\cos x##. In fact the expressions for different values of ##n## higher than 1 (like ##n=2## and ##n=3##) are important trigonometric identities.

i.e. why can´t I solve question nr 1 the way I did question nr 2?

In no. 2, you're just factoring out the ##\sin x##. That's completely valid. ##\sin^2 x## is the conventional shorthand for ##(\sin x)^2##. This is the square of the sine of angle ##x##. This is completely different from ##\sin 2x##, which is the sine of the angle ##2x##.

I was also wondering if sin2x is the same as 2sinx? does it make a difference where I place the 2?

Huge difference, just like for the cosine.
 
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Curious3141 said:
Because (in general) ##\cos nx \neq n\cos x##. In fact the expressions for different values of ##n## higher than 1 (like ##n=2## and ##n=3##) are important trigonometric identities.



In no. 2, you're just factoring out the ##\sin x##. That's completely valid. ##\sin^2 x## is the conventional shorthand for ##(\sin x)^2##. This is the square of the sine of angle ##x##. This is completely different from ##\sin 2x##, which is the sine of the angle ##2x##.



Huge difference, just like for the cosine.

Perfect. Now I get it! thanks a lot!
 
Attis said:
I was also wondering if sin2x is the same as 2sinx? does it make a difference where I place the 2?
Check out the graphs:

cd98f00b204e9800998ecf8427efi199hvhk6&f=HBQTQYZYGY4TSM3EMI3WENBTHAYDCNBVGU3DEMTEGA4GEMZXGEZAaaaa.gif


To put a 2 in front of sin x is to double the amplitude. To put a 2 in front of the x in sin x is to double the frequency.

Wolfram Alpha is great for stuff like this.
 
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Fredrik said:
Check out the graphs:

cd98f00b204e9800998ecf8427efi199hvhk6&f=HBQTQYZYGY4TSM3EMI3WENBTHAYDCNBVGU3DEMTEGA4GEMZXGEZAaaaa.gif


To put a 2 in front of sin x is to double the amplitude. To put a 2 in front of the x in sin x is to double the frequency.

Wolfram Alpha is great for stuff like this.

Ok, thanks for explaining!
 
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