Differentail Eq. For circle passing through origin

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can some 1 help me with it pleasezz
 
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can u post the qstn pleasezz? :biggrin:
 
question is find the differential eq. for circle that passes through origin.
 
That can't be all there is to it. There are an infinite number of circles that pass through the origin.
 
exactly...i m v confused...thats all wat the question is for assignment i ve to submit tomorrow
i just kno the answer but don't kno anything else
ans: 2ay''+y'(raise to the power 3)=0
 
2ay + y^3 = 0.
2a = -y^2
This represents a circle!
 
yesss!
thx a lot :)
 
but how will we come to this eq. from start if we dint know the DE?
 
what is the eq you were given for circle that pass in (0,0) ? is it like this one : (x-a)^2 +(y-b)^2 = a^2 +b^2
 
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  • #10
How about writing out the entire problem as it was given?
Isma said:
just kno the answer but don't kno anything else
ans: 2ay''+y'(raise to the power 3)=0
How can that be an answer when there was no "a" in the original question?

Vaishakh said:
2ay + y^3 = 0.
2a = -y^2
This represents a circle!

In what sense does that represent a circle?

Isma said:
yesss!
thx a lot :)

Did you understand what he meant??

Any circle, that passes through the origin can be written
(x- a)2+ (y- b)2= a2+ b2
(I just noticed that ziad1985 said that!)

Differentiating wrt x, 2(x-a)+ 2(y-b)y'= 0.

Differentiating again, 2+ 2y'2+ 2(y-b)y"= 0.

Now combine those into an equation that does not have either a or b in it.
 
  • #11
actually...this assignment was given just after 1st lecture on DE in class...so i was v much messed up in mind...nd abt that thanks heheheh...it made sense at that moment but not in the next 1:)
i really appreciate u helpin me ...i m going to solve it like that
thx!
 

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