Differentation Problem (involves product rule)

AI Thread Summary
To differentiate the function F(x) = (x-1)(x-2)(x-3) using the product rule for three terms, one can apply the formula for the derivative of a product of functions. Alternatively, the equation can be rewritten as F(x) = (x-1)(x^2-5x+6) to simplify the differentiation process. Both methods yield the same result after calculation. Expanding the function before differentiating is often easier and more straightforward. Ultimately, both approaches confirm that the derivative is 3x^2 - 12x + 11.
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Here's the equation:

F(x) = (x-1)(x-2)(x-3)


I know how to diff. using the product rule when you only have 2 equations, but not 3.I looked at the examples in my book and none of them show how you would work out this sort of problem. So if someone could give me the basic overview of how to differentiate a problem like this, I'd greatly appreciate it.
 
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Just wondering something...

Could I change the equation to read like this before diff. it:

F(x) = (x-1)(x^2-5x+6) ?



Then I could just use the product rule from there.
 
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consider u,v,w as a function of x

then \frac{d}{dx}uvw = uv \frac{d}{dx}w + vw\frac{d}{dx}u + uw\frac{d}{dx}v
 
Just expand it then differentiate. According to Maple, you get the same answer.


Here is when you differentiate 3 terms

> R3 := diff((x-1)*(x-2)*(x-3),x);

R3 := (x - 2) (x - 3) + (x - 1) (x - 3) + (x - 1) (x - 2)

> R4 := expand(R3);
R4 := 3 x^2 - 12 x + 11


Here is when you expand it then differentiate it

R1 := expand((x-1)*(x-2)*(x-3));
R1 := x^3 - 6 x^2 + 11 x - 6

> R2 := diff(R1,x);
R2 := 3 x^2 - 12 x + 11



You end with the same answer. Just expand it; it's much easier.
 
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