- #1
cse63146
- 452
- 0
Homework Statement
Solve the following IVP:
[tex]\frac{dy}{dt} = \frac{1}{2y+3}[/tex] y(0) = 1
Homework Equations
The Attempt at a Solution
[tex]\frac{dy}{dt} = \frac{1}{2y+3}[/tex]
[tex]\Rightarrow \int 2y + 3 dy= \int dt[/tex]
[tex]\Rightarrow y^2 + 3y= t +c[/tex] where C is a constant
Kinda stuck now. Any hints?