Differential Equations? Fill in the table.

ani9890
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Fill in the missing values in the table given if you know that dy/dt=0.2y. Assume the rate of growth given by dy/dt is approximately constant over each unit time interval and that the initial value of y is 6.

Table:
t-0-1-2-3-4
y-6-?-?-?-?
(fill in the missing values where there is a question mark)

I got:
t = 1, y = 7.33
At t = 2 , y = 8.95
At t = 3 , y =10.93
At t = 4 , y = 13.35
using y=6e^(.2t)

but it is wrong, Help?
 
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ani9890 said:
Fill in the missing values in the table given if you know that dy/dt=0.2y. Assume the rate of growth given by dy/dt is approximately constant over each unit time interval and that the initial value of y is 6.

Table:
t-0-1-2-3-4
y-6-?-?-?-?
(fill in the missing values where there is a question mark)

I got:
t = 1, y = 7.33
At t = 2 , y = 8.95
At t = 3 , y =10.93
At t = 4 , y = 13.35
using y=6e^(.2t)

but it is wrong, Help?

You have apparently just plugged the t values into the exact solution. But that is not what the problem asks you to do. What you are asked to do looks a lot like Euler's approximation method. So start with knowing at t=0 the slope is ##.2(6)##, assume that constant slope to get the value at ##t=1##. Then do the same thing for the next steps.
 
Thank you, I redid the problem using y₂ = y₁ + m(x₂ - x₁) and got:

t --- y
0 .. 6
1 .. 7.2
2 .. 8.64
3 .. 10.368
4 .. 12.4416

can you please check if this is correct?
Thank you
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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