Differential Equations: If y(1) =3 then y(1/2) = ?

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SUMMARY

The differential equation presented is of the form ty'(t) + tln(t)y(t) = 0, with the initial condition y(1) = 3. To find y(1/2), the equation can be solved using separation of variables or linear methods. The suggestion to factor out t simplifies the equation, making it easier to solve for y(t). The solution process involves integrating and applying the boundary conditions to determine the value of y(1/2).

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  • Understanding of differential equations, specifically first-order linear equations.
  • Familiarity with separation of variables technique in solving differential equations.
  • Knowledge of boundary value problems and initial conditions.
  • Basic logarithmic properties and their application in calculus.
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Northbysouth
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Homework Statement


If y satisfies the differential equation:

ty'(t) + tln(t)y(t) = 0

and y(1) = 3 then y(1/2) = ?

I have attached an image of the question with the possible solutions:


Homework Equations





The Attempt at a Solution



Initially I tried plugging in t=1 and y(1) = 3 giving me:

y'(1)+3ln(1) = 0

Hence y'(1) = 0

I did the same for t=1/2

1/2[y'(1/2) + ln(1/2)y(1/2)] = 0

But this doesn't seem to help me. Any suggestions would be appreciated.
 

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Why don't you just solve the DE and put in the boundary conditions? It looks to be separable and linear so you have a couple of options.
 
Northbysouth said:

Homework Statement


If y satisfies the differential equation:

ty'(t) + tln(t)y(t) = 0

and y(1) = 3 then y(1/2) = ?

I have attached an image of the question with the possible solutions:

Homework Equations



The Attempt at a Solution



Initially I tried plugging in t=1 and y(1) = 3 giving me:

y'(1)+3ln(1) = 0

Hence y'(1) = 0

I did the same for t=1/2

1/2[y'(1/2) + ln(1/2)y(1/2)] = 0

But this doesn't seem to help me. Any suggestions would be appreciated.
To help you solve the D.E., factor out t .
 

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