Differential equations. linear system.

dictation
Messages
2
Reaction score
0

Homework Statement



G(t) is nxn matrix depends on t.
Show that solutions of x'=G(t)x form an n-dim subspace of C1(R+,Rn).


The Attempt at a Solution



So I can show closure, addition of solutions returns some combo inside R^n, and same with scalar multiplication. I need to show dimension..
 
Physics news on Phys.org
Since Gn is an n by n matrix, x must be a column matrix with n rows. Let x1(t) be the solution with x(0)1= (1, 0, 0, ..., 0)T. Let x2(t) be the solution with x2(0)= (0, 1, 0, ..., 0)T. Let x3(t) be the solution with x3(0)= (0, 0, 1, ..., 0)T. Continue until you have xn(t) defined as the solution with xn(t)= (0, 0, 0, ..., 1)T. Show that they are independent, by showing that the only solution to the differential equation with x(0)= (0, 0, 0, ..., 0)T is the 0 function, and that the solution with x(t)= (a1, a2, a3, ..., an) is equal to a1x1(t)+ a2x2(t)+ a3x3(t)+ ...+ anxn(t) by showing that they both satisfy the differential equation and the same initial condition.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top