(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the particular solution to the differential equation using method of variation of parameters:

4y''-4y'+y=16e^(t/2)

3. The attempt at a solution

Set 4y''-4y'+y=0

then the homogeneous solution is:

y= c1*e^(t/2)+c2*te(t/2)

set y1= e^(t/2), y2= te^(t/2)

then y1' = (1/2)*e^(t/2), y2' = (t/2+1)*e^(t/2)

Wronskian = W(y1,y2) = e^t

http://img140.imageshack.us/img140/1822/dif1.jpg [Broken]

I know i did something wrong because checking my answer by plugging Y(t) back in to the O.D.E , left hand side and right hand side dont check out.

By using method of undetermined coefficients, Y(t) = 2t^2*e^(t/2), which is the correct answer.

So question is what did i do wrong using method of variation of parameters?

Thanks

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# Homework Help: Differential Equations: Variation of Parameters

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